Program to implement a Quadratic equation in Java

In this program, you will learn to find all roots of a quadratic equation in Java.

Also, you can use the Java compiler to compile a program.

Program to implement a Quadratic equation in Java

Program to implement all Roots of a Quadratic equation in java

The standard form of equation is:

ax2 + bx + c = 0, where
a, b and c are real numbers and
a ≠ 0

The term b2-4ac is known as the determinant of an equation. The determinant tells the nature of the roots.

  • If the determinant is greater than 0, the roots are real and different.
  • And determinant is equal to 0, the roots are real and equal.
  • If the determinant is less than 0, the roots are complex and different.
SOURCE CODE.
import java.util.*;
class quadratic3
{
	public static void main(String args[])
	{
		int e,a,b,c;
		double l,x,y;
		Scanner s= new Scanner(System.in);
		System.out.println("Enter value a,b,c:");
		a=s.nextInt();
		b=s.nextInt();
		c=s.nextInt();
		
		e=b*b-4*a*c;
		if(e<0)
		{
			System.out.println("NOT REAL");
		}
			else if(e == 0) 
		{
                 x = -b / (2.0 * a);
                System.out.println("The root is " + x);
		}
		else 
		{
			l=Math.sqrt(e);
			x= (-b+l)/(2*a);
			y= (-b-l)/(2*a);
			System.out.println("equation= "+x+" & "+y);
		}
	}// END OF MAIN
}//END OF CLASS	

OUTPUT.

C:\A>javac quadratic3.java
C:\A>java quadratic3
Enter value a,b,c:
1
4
4
The root is -2.0

OR

C:\A>javac quadratic3.java
C:\A>java quadratic3
Enter value a,b,c:
1
5
2
equation= -0.4384471871911697 & -4.561552812808831

Also view: – Command-Line program find the Largest number

About Ashishkumar Vishwakarma

I am Ashish- a Developer live in Mumbai.

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3 Comments on “Program to implement a Quadratic equation in Java”

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